Interest Problems

    This topic explains simple interest and compound interest through a series of problems and examples. Compounding continuously and the annual percentage rate is also worked on. Attention is given to the problem of finding the doubling time for an investment.

Definition (Simple Interest and Future Value) If a sum of money (called the principal) is invested for a period of time interest problems _gr_1.gif] at an interest rate interest problems _gr_2.gif] per period, the simple interest is given by the formula: interest problems _gr_3.gif] and the future value of the investment is interest problems _gr_4.gif] interest problems _gr_5.gif] interest problems _gr_6.gif]

Example (Future Value for Simple Interest) If $21,200 is invested at an annual simple interest rate of 5%, what is the future value of the investment after 2 years?
    The future value is given by the formula interest problems _gr_7.gif] and since interest problems _gr_8.gif] interest problems _gr_9.gif] and   interest problems _gr_10.gif] we have
    
interest problems _gr_11.gif]
interest problems _gr_12.gif]

Example (Interest for Simple Interest) If $7,700 is invested for 5 years at an annual simple interest rate of 15%, how much interest is earned?
    The interest earned is interest problems _gr_13.gif] where interest problems _gr_14.gif] interest problems _gr_15.gif] and interest problems _gr_16.gif] so we have

interest problems _gr_17.gif]
interest problems _gr_18.gif]

Example (Principal for Simple Interest) A firm buys 15 file cabinets at $166.23 each, with the bill due in 90 days. How much must the firm deposit now to have enough to pay the bill if money is worth 6% per year? Use 360 days in a year.
    The future value is interest problems _gr_19.gif] We are looking for the principal, interest problems _gr_20.gif] and interest problems _gr_21.gif] We use the formula interest problems _gr_22.gif] interest problems _gr_23.gif] and we have interest problems _gr_24.gif] and solving for interest problems _gr_25.gif] we get

interest problems _gr_26.gif]
interest problems _gr_27.gif]

Example (Doubling Time for Simple Interest) If $5000 is invested at 8% annual simple interest, how long does it take to double to $10,000?
    The future value is given by the formula interest problems _gr_28.gif] and we are given a value of interest problems _gr_29.gif] We are asked to find interest problems _gr_30.gif] when interest problems _gr_31.gif] and interest problems _gr_32.gif] We have
    
interest problems _gr_33.gif]

interest problems _gr_34.gif]

interest problems _gr_35.gif]

interest problems _gr_36.gif] years.
interest problems _gr_37.gif]

Definition (Periodic Compounding Interest) If interest problems _gr_38.gif] dollars is invested for interest problems _gr_39.gif] years at a nominal interest rate interest problems _gr_40.gif] componded interest problems _gr_41.gif] times per year, then the total number of compounded periods is interest problems _gr_42.gif] and the interest rate per period is interest problems _gr_43.gif] and the future value is interest problems _gr_44.gif] or

interest problems _gr_45.gif]

Example (Future Value for Compounding Periocially) Find the future value if $3500 is invested for 6 years at 8% compounded quarterly.
    The future value is given by the formula interest problems _gr_46.gif] where interest problems _gr_47.gif] interest problems _gr_48.gif] and interest problems _gr_49.gif] so we have
    
interest problems _gr_50.gif]
interest problems _gr_51.gif]

Example (Interest for Compounding Periocially) Find the interest that will be earned if $5000 is invested for 3 years at 10% compounded semiannually.
    The interest earned is the future value minus the principal. So we find the future value first. The future value is given by interest problems _gr_52.gif] where interest problems _gr_53.gif] interest problems _gr_54.gif] and interest problems _gr_55.gif] so we have
    
interest problems _gr_56.gif]

Therefore, the interest earned is interest problems _gr_57.gif] interest problems _gr_58.gif]

Example (Principal for Compounding Periocially) What present value amounts to $100,000 if it is invested for 10 years at 8% compounded quarterly?
    The present value can be found using the formula interest problems _gr_59.gif] where the future value interest problems _gr_60.gif] interest problems _gr_61.gif] and interest problems _gr_62.gif] so we have

interest problems _gr_63.gif]

interest problems _gr_64.gif]

interest problems _gr_65.gif]

interest problems _gr_66.gif]
interest problems _gr_67.gif]

Example (Doubling Time for Componding Periocially) How long in years would $700 have to be invested at 11.9% compounded monthly to have $1,400?
    The future value is interest problems _gr_68.gif] and can be found using the formula interest problems _gr_69.gif] where interest problems _gr_70.gif] interest problems _gr_71.gif] and interest problems _gr_72.gif] so we have
    
interest problems _gr_73.gif]

interest problems _gr_74.gif]

interest problems _gr_75.gif]

interest problems _gr_76.gif]

interest problems _gr_77.gif]

interest problems _gr_78.gif] years.
interest problems _gr_79.gif]

Definition (Continuous Compounding Interest)  If interest problems _gr_80.gif] dollars is invested for interest problems _gr_81.gif] years at an interest rate interest problems _gr_82.gif] compounded continuously, then the future value is given by interest problems _gr_83.gif]

Example (Future Value for Compounding Continuously) What lump sum do parents need to deposit in an account earning 9%, compounded continuously, so that it will grow to $40,000 for their daughter's college tuition in 18 years?
    The future value is $40,000 and is given by the formula interest problems _gr_84.gif] where interest problems _gr_85.gif] and interest problems _gr_86.gif] and so we have

interest problems _gr_87.gif]

interest problems _gr_88.gif]

interest problems _gr_89.gif]
interest problems _gr_90.gif]

Example (Interest for Compounding Continuously) Which investment will earn more money, a $1000 investment for 6 years at 8% componded annually, or a $1000 investment for 6 years compounded continuously?  
    The investment that is compounding annually will have future value of interest problems _gr_91.gif] where interest problems _gr_92.gif] and interest problems _gr_93.gif] which is interest problems _gr_94.gif] interest problems _gr_95.gif] The investment that is compounding continuously will have future value interest problems _gr_96.gif] where interest problems _gr_97.gif] and interest problems _gr_98.gif] which is interest problems _gr_99.gif] interest problems _gr_100.gif] Thus, the investment which is compounding continuously is the better investment. interest problems _gr_101.gif]

Example (Principal for Compounding Continuously) What present value needs to be deposited to have $20,000 in 3 years with an investment that is compounded continuously at 4%?
    The future value is 20000 and is given by the formula interest problems _gr_102.gif] where interest problems _gr_103.gif] and interest problems _gr_104.gif] and so we have

interest problems _gr_105.gif]

interest problems _gr_106.gif]

interest problems _gr_107.gif]
interest problems _gr_108.gif]

Example (Doubling Time for Compounding Continuously) (a) How long in years would $700 have to be invested at 12.3%, componded continuously, to have interest problems _gr_109.gif]
    The future value is interest problems _gr_110.gif] and is given by the formula interest problems _gr_111.gif] where interest problems _gr_112.gif] interest problems _gr_113.gif] and interest problems _gr_114.gif] and so we have

interest problems _gr_115.gif]

interest problems _gr_116.gif]

interest problems _gr_117.gif]

interest problems _gr_118.gif] years

    (b) Find the doubling time for an investment with interest rate interest problems _gr_119.gif] and principal interest problems _gr_120.gif] where interest problems _gr_121.gif] is in years.
    The doubling time is given by the future value formula where interest problems _gr_122.gif] is the present value, interest problems _gr_123.gif] is the interest rate, and interest problems _gr_124.gif] is the time in years, so we have
    
interest problems _gr_125.gif]

         interest problems _gr_126.gif]
        
interest problems _gr_127.gif]

interest problems _gr_128.gif]
interest problems _gr_129.gif]

Definition (Annual Percentage Yield) If interest problems _gr_130.gif] is the number of compounding periods per year, then interest problems _gr_131.gif] is the interest rate per period and if interest problems _gr_132.gif] is the annual interest rate for an investment, then the annual percentage yield is defined by the formula

interest problems _gr_133.gif]

For compounded continuously invesment the A.P.Y. is defined by the formula

interest problems _gr_134.gif]

Example (Annual Percentage Yield) Suppose there are three investements to invest in (a) one at 10% compounded annually, (b) another at 9.8% compounded quarterly, and (c) a third investment at 9.65% compounded continuously. Which investment is best?
    For the first investment interest problems _gr_135.gif] and interest problems _gr_136.gif] and so will have A.P.Y. interest problems _gr_137.gif] interest problems _gr_138.gif] For the second investment we have interest problems _gr_139.gif] and interest problems _gr_140.gif] and so we have A.P.Y. interest problems _gr_141.gif] interest problems _gr_142.gif] For the last investment we have A.P.Y. interest problems _gr_143.gif] interest problems _gr_144.gif] and so the best investment is the second. interest problems _gr_145.gif]

Example (Interest Problems) (a) What is the present value of an investment at 6% annual simple interest if it is worth $832 in 8 months?
    The future value is 832 and is given by interest problems _gr_146.gif] where interest problems _gr_147.gif] and interest problems _gr_148.gif] and so we have
    
interest problems _gr_149.gif]

interest problems _gr_150.gif]

interest problems _gr_151.gif]

    (b) How much more interest will be earned if $5000 is invested for 6 years at 7% compounded continuously, instead of at 7% compounded quarterly?
    If we use compounding continuously then the future value is interest problems _gr_152.gif] where interest problems _gr_153.gif] interest problems _gr_154.gif] and interest problems _gr_155.gif] and so we have interest problems _gr_156.gif] interest problems _gr_157.gif] Thus the interest earned is interest problems _gr_158.gif] If we use compounding quarterly then the future value is given by interest problems _gr_159.gif] where interest problems _gr_160.gif] interest problems _gr_161.gif] and interest problems _gr_162.gif] and so we have future value of interest problems _gr_163.gif] interest problems _gr_164.gif] Thus for compounding quarterly we have interest earned as interest problems _gr_165.gif] Therefore, the first investment is better by   interest problems _gr_166.gif] interest problems _gr_167.gif]

Cite this as:
Interest Problems
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/interest-problems.html
 
    
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