Law of Sines

     The law of sines is an essential tool in trying to solve any problem involving triangles. For example, if we are given a triangle and we know all three angles and one side, then we can use the law of sines to find the other two sides. Even more, as the following theorem shows, the law of sines is really three relationships in one statement.
    Basically, the law of sines states that  in any triangle, the ratio of the sine of an angle to the side opposite that angle is equal to the ratio of the sine of another angle to the side opposite that angle. The laws of sines is usually for solving triangles SSA (two sides and an angle opposite one of them) and AAS (or ASA) (two angles and any side).

Proposition (Law of Sines) Let law of sines _gr_1.gif] law of sines _gr_2.gif] and law of sines _gr_3.gif] be the angles of a triangle. If law of sines _gr_4.gif] is the length of the side opposite angle law of sines _gr_5.gif] law of sines _gr_6.gif] is the length of the side opposite angle law of sines _gr_7.gif] and law of sines _gr_8.gif] is the length of the side opposite angle law of sines _gr_9.gif] then

law of sines _gr_10.gif]

Example (Law of Sines) When the angle of elevation of the sun is law of sines _gr_11.gif] a telephone pole that is tilted at an angle of law of sines _gr_12.gif] directly away from the sum casts a shadow of 21 feet long on  level ground. Approximate the length of the pole.

    Solution. The angle of elevation of the telephone is law of sines _gr_13.gif] and we are given the angle opposite the telephone pole as law of sines _gr_14.gif] Therefore, the angle opposite the shadow is law of sines _gr_15.gif]  Let law of sines _gr_16.gif] be the length of the telephone pole. Using the law of sines, we find
    
law of sines _gr_17.gif]

Since, law of sines _gr_18.gif] the length of the telephone pole is approximately 33 feet. law of sines _gr_19.gif]

Example (Law of Sines) In a certain isosceles triangle, the angle between the two equal sides is law of sines _gr_20.gif] and the side opposite that angle is law of sines _gr_21.gif] cm. Find the lengths of the two equal sides.

    Solution. Let law of sines _gr_22.gif] be the length of each of the two equal sides. The angles opposite the two equal sides are law of sines _gr_23.gif] because law of sines _gr_24.gif] Using the law of sines we have,

law of sines _gr_25.gif]

Since, law of sines _gr_26.gif] the length of each of the two equal sides is law of sines _gr_27.gif] law of sines _gr_28.gif]

Example (Law of Sines) A point law of sines _gr_29.gif] on level ground is 3.0 kilometers due north of a point law of sines _gr_30.gif] A runner proceeds in the direction law of sines _gr_31.gif] from law of sines _gr_32.gif] to a point law of sines _gr_33.gif] and then from law of sines _gr_34.gif] to law of sines _gr_35.gif] in the direction law of sines _gr_36.gif] Approximate the distance run.

    Solution. Let law of sines _gr_37.gif] be the distance from law of sines _gr_38.gif] to law of sines _gr_39.gif] and let law of sines _gr_40.gif] be the distance between law of sines _gr_41.gif] to law of sines _gr_42.gif] The angle opposite of the 3 miles is law of sines _gr_43.gif] The law of sines yields

law of sines _gr_44.gif]

Since, law of sines _gr_45.gif] the distance between Q to law of sines _gr_46.gif] is 1.8 kilometers. The remaining angle of the triangle is law of sines _gr_47.gif] So

law of sines _gr_48.gif]

Since, law of sines _gr_49.gif] the distance between law of sines _gr_50.gif] to law of sines _gr_51.gif] is 4 kilometers. Therefore, the total distanced traveled is approximately law of sines _gr_52.gif] law of sines _gr_53.gif]

Cite this as:
Law Of Sines
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
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