Polynomial Graph
The graphs of linear polynomials and quadratic polynomials are lines and parabolas, respectively. The emphasis of this topic is on a polynomial graph of a polynomial function whose degree is greater than 2.
Theorem (Polynomial Graph) Properties. Suppose
is a polynomial function of degree
![]()
(i) The polynomial graph of
is far from the
-axis when
is large.
(ii) The polynomial graph of
crosses the
-axis at most
times.
(iii) The polynomial graph of
has at most
turning points (relative extrema).
(iv) The polynomial graph represents a function whose domain is all real numbers.
(v) The polynomial graph represents a continuous function.
Example (Polynomial Graph) Properties. The graph of the fourth degree polynomial
defined by
![]()
is shown below: Notice that when
grows larger and larger the values of
also grow larger and larger. We write this using
as
Similarly,
as
Also notice that the graph of
crosses the
-axis 3
times. Notice that the graph of
has 3
turning points.
![polynomial graph _gr_24.gif]](pages/polynomial-graph/Images/polynomial-graph_gr_24.gif)
The following theorem is known as the intermediate value theorem for polynomials and basically says that if
is a continuous function on the closed interval
and
is some number strictly between
and
, then there exists at least one number
between
and
such that
Theorem (Polynomial Graph) Intermediate Value Theorem. If
is a polynomial function and
for
then
takes on every value between
and
in the interval
The intermediate value theorem says that if
and
have different signs then the function
has at least one
between
and
with
Or plainly said, if
and
have different signs then the is an
-intercept between
and
This is an important existence theorem because solving the equation
may be difficult, and even algebraically impossible.
Example (Polynomial Graph) Intermediate Value Theorem. Show that the polynomial function
defined by
![]()
has an
-intercept between
and
.
Solution. Can we use the intermediate value theorem? We check that
and
have different signs which is true because
and
Therefore, the intermediate value theorem applies and so the function
must have at least one
-intercept between
and
As a side note, since
and
does this mean that
does not have any
-intercepts between
and
The answer is no, notice that
and
The graph of
follows:
![polynomial graph _gr_77.gif]](pages/polynomial-graph/Images/polynomial-graph_gr_77.gif)
Polynomial Graph
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/polynomial-graph.html


