Properties of Mappings
Proposition (Properties of Mappings) Let
(i) Then,
is onto if and only if there exists a mapping
such that
(ii) Then,
is one-to-one if and only if for every set
and all mappings
and
if
then
![]()
(iii) Then,
is onto if and only if there exists a mapping
such that
(iv) Then,
is one-to-one if and only if for every set
and all mappings
and
if
then
![]()
Proof. (i): Assume that
is onto and let
For each
there exists
such that
(Axiom of Choice). For each
pick one
such that
and let
be the set of all such chosen pairs
Then each
is the first component of one ordered pair in
so
is a mapping. Let
if and only if
Then
and so
Conversely, assume that
and there is a mapping
with
Given
let
Then
so
is onto.
(ii): Assume that
is onto and let
Then there exists
with
If
then
Since
for all
it follow
Assume that
is not onto and let
such that
Define
by
for all
and define
by
for all
and
Then
since
On the other hand
and
since
Since
and
have the same domain and same codomain,
![]()
(iii): Assume that
is one-to-one and let
Pick
(Axiom of Choice) Let
Since
is one-to-one, each element of
is the first entry in one and only one ordered pair in
Hence,
is a mapping. Let
be
where
Then
and since
has domain and codomain
we have
Conversely, assume that for
there exists
with
and that
Then, if
then
and so
is one-to-one.
(iv): Assume that
is one-to-one,
and
Then
and so
Since
is one-to-one,
Since
for all
and
and
have the same domain and same codomain,
Conversely, assume that
is not one-to-one. Then there exists
in
with
Let
and define
by
and define
by
and
Then
but
since
and
Properties Of Mappings
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/properties-of-mappings.html


